Compound Interest MCQ Question with Answer

Correct Answer : A

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Explanation

Let the sum be Rs. x. Then,

   C.I. = [ x * (1 + (( 50/(3*100))³ - x ] = ((343x / 216) - x) = 127x / 216

   127x /216 = 1270 or x = (1270 * 216) / 127 = 2160.

   Thus, the sum is Rs. 2160

    S.I. = Rs ( 2160 * (50/3) * 3 * (1 /100 ) ) = Rs. 1080.

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Correct Answer : C

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Explanation

Let the sum be Rs. x. Then,

            C.I. = x ( 1 + ( 10 /100 ))² - x = 21x / 100 ,

            S.I. = (( x * 10 * 2) / 100) = x / 5

            (C.I) - (S.I) = ((21x / 100 ) - (x / 5 )) = x / 100

             ( x / 100 ) = 632 , x = 63100.

             Hence, the sum is Rs.63,100.

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Correct Answer : D

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Explanation

Let the rate be R% p.a. then,

[ 18000 ( 1 + ( R / 100 )² ) - 18000 ] - ((18000 * R * 2) / 100 ) = 405

18000 [ ( 100 + (R / 100 )² / 10000) - 1 - (2R / 100 ) ] = 405

18000[( (100 + R ) ² - 10000 - 200R) / 10000 ] = 405

9R² / 5 = 405 , R² =((405 * 5 ) / 9) = 225

R = 15.

Rate = 15%.

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Correct Answer : A

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Explanation

S.I on rs.7350 for 1 year=rs.(8575-7350)=rs.1225.

Rate=(100*1225/7350*1)%=16 2/3%

Let the sum be rs.x.then,

X(1+50/3*100)²=7350

X*7/6*7/6=7350

X=(7350*36/49)=5400.

Sum=rs.5400.

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Correct Answer : C

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Explanation

Let the sum be rs.P.then

P(1+R/100)³=6690…(i) and   P(1+R/100)⁶=10035…(ii)

On dividing, we get (1+R/100)³=10025/6690=3/2.

Substituting this value in (i),we get:

P*3/2=6690 or P=(6690*2/3)=4460

Hence, the sum is rs.4460.

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Correct Answer : C

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Explanation

P(1+R/100)¹⁵=2P

(1+R/100)¹⁵=2P/P=2

LET P(1+R/100)ⁿ=8P

(1+R/100)ⁿ=8=2³={(1+R/100)¹⁵}³[USING (I)]

(1+R/100)^N=(1+R/100)⁴⁵

n=45.

Thus, the required time=45 years.

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