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A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:

A. 35

B. 3623

C. 3712

D. 40

Correct Answer :

D. 40


Let distance = x km and usual rate = y kmph.
Then, xy - xy+3 = 4060          2y(y + 3) = 9x ....(i)
And, xy-2 - xy = 4060         y(y - 2) = 3x ....(ii)
On dividing (i) by (ii), we get: x = 40.

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