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A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ?

A. 44 km/hour

B. 46 km/hour

C. 48 km/hour

D. 50 km/hour

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Correct Answer : C.

Speed while going = 40 km/hr
Speed while returning = 150% of 40 = 60 km/hr
Average speed =

\frac{2 x y}{x + y}

= \frac{2 \times 40 \times 60}{40 + 60} = \frac{4800}{100} = 48 K m / h r

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