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A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

A. 48 km/hr

B. 54 km/hr

C. 66 km/hr

D. 82 km/hr

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Correct Answer : D.

L e t t h e s p e e d o f t h e s e c o n d t r a i n b e x k m / h r . R e l a t i v e s p e e d = (x + 50) k m / h r = [(x + 50) x \frac{5}{18}] m / s e c = [\frac{250 + 5 x}{18}] m / s e c . D i s \tan c e c o v e r e d = (108 + 112) = 220 m . T h e r e f o r e \frac{220}{(\frac{250 + 5 x}{18})} = 6 \Rightarrow 250 + 5 x = 660 \Rightarrow x = 82 k m / h r .

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