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5 sec

6 sec

7 sec

10 sec

B. 6 sec

$Speedoftrainrelativetoman=(60+6)km/hr=66km/hr.\phantom{\rule{0ex}{0ex}}=\left(66x\frac{5}{18}\right)m/sec\phantom{\rule{0ex}{0ex}}=\left(\frac{55}{3}\right)m/sec.\phantom{\rule{0ex}{0ex}}\therefore Timetakentopasstheman=\left(110x\frac{3}{55}\right)sec=6sec.$