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A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

A. 69.5 km/hr

B. 70 km/hr

C. 79 km/hr

D. 79.2 km/hr

Correct Answer : D.


Let the length of the train be x metres and its speed by y m/sec.  Then, xy = 8 ⇒ x = 8y  Now, x + 26420 = y  ⇒8y + 264 = 20y  ⇒ y = 22.  Therefore Speed = 22 m/sec =22 x 185 km/hr = 79.2 km/hr. 

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