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4

According to Manning's formula, the discharge through an open channel is (where M = Manning's constant)

A. A × M × m1/2 × i2/3

B. A × M × m2/3 × i1/2

C. A1/2 × M2/3 × m × i

D. A2/3 × M1/3 × m × i

Correct Answer :

B. A × M × m2/3 × i1/2


Related Questions

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4

In a forced vortex, the velocity of flow everywhere within the fluid is

A. Maximum

B. Minimum

C. Zero

D. Nonzero finite

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4

Buoyant force is

A. The resultant force acting on a floating body

B. The resultant force on a body due to the fluid surrounding it

C. Equal to the volume of liquid displaced

D. The force necessary to maintain equilibrium of a submerged body

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4

When the water level on the downstream side of a weir is above the top surface of a weir, the weir is known as

A. Narrow-crested weir

B. Broad-crested weir

C. Ogee weir

D. Submerged weir

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4

The intensity of pressure on an immersed surface __________ with the increase in depth.

A. Does not change

B. Increases

C. Decreases

D. None of these

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4

An opening in the side of a tank or vessel such that the liquid surface with the tank is below the top edge of the opening, is called

A. Weir

B. Notch

C. Orifice

D. None of these

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4

The loss of head due to viscosity for laminar flow in pipes is (where d = Diameter of pipe, l = Length of pipe, v = Velocity of the liquid in the pipe, μ = Viscosity of the liquid, and w = Specific weight of the flowing liquid)

A. 4μvl/wd²

B. 8μvl/wd²

C. 16μvl/wd²

D. 32μvl/wd²

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4

The centre of pressure acts __________ the centre of gravity of immersed surface.

A. At

B. Above

C. Below

D. None of these

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4

The unit of viscosity is

A. Metres² per sec

B. kg-sec/metre

C. Newton-sec per metre²

D. Newton-sec per meter

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4

According to Francis formula, the discharge over a rectangular weir is (where n = Number of end contractions)

A. (2/3) × Cd (L - nH) × √(2gh)

B. (2/3) × Cd (L - 0.1nH) × √(2g) × H3/2

C. (2/3) × Cd (L - nH) × √(2g) × H²

D. (2/3) × Cd (L - nH) × √(2g) × H5/2

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4

A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be

A. 2A × √H₁/Cd × a × √(2g)

B. 2A × √H₂/Cd × a × √(2g)

C. 2A × (√H₁ - √H₂)/Cd × a × √(2g)

D. 2A × (√H3/2 - √H3/2)/Cd × a × √(2g)

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4

According to Bernoulli's equation

A. Z + p/w + v²/2g = constant

B. Z + p/w - v²/2g = constant

C. Z - p/w + v²/2g = constant

D. Z - p/w - v²/2g = constant

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4

Uniform flow occurs when

A. The direction and magnitude of the velocity at all points are identical

B. The velocity of successive fluid particles, at any point, is the same at successive periods of time

C. The magnitude and direction of the velocity do not change from point to point in the fluid

D. The fluid particles move in plane or parallel planes and the streamline patterns are identical in each pleasure

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4

The body will sink down if the force of buoyancy is __________ the weight of the liquid displaced.

A. Equal to

B. Less than

C. More than

D. None of these

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4

A piece weighing 3 kg in air was found to weigh 2.5 kg when submerged in water. Its specific gravity is

A. 1

B. 5

C. 7

D. 6

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4

Dynamic viscosity of most of the gases with rise in temperature

A. Increases

B. Decreases

C. Remain unaffected

D. Unpredictable

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4

The increase in pressure at the outer edge of a drum of radius (r) completely filled up with liquid of density (ρ) and rotating at (ω) rad/s is

A. ρ ω2 r2

B. 2ρ ω2 r2

C. ρ ω2 r2/2

D. ρ ω2 r2/4

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4

If no resistance is encountered by displacement, such a substance is known as

A. Fluid

B. Water

C. Gas

D. Ideal fluid

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4

For similarity, in addition to models being geometrically similar to prototype, the following in both cases should also be equal

A. Ratio of inertial force to force due to viscosity

B. Ratio of inertial force to force due to gravitation

C. Ratio of inertial force to force due to surface tension

D. All the four ratios of inertial force to force due to viscosity, gravitation, surface tension, and elasticity

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4

An ideal flow of any fluid must fulfil the following

A. Newton's law of motion

B. Newton's law of viscosity

C. Pascal' law

D. Continuity equation

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4

The buoyancy depends upon the

A. Weight of the liquid displaced

B. Pressure with which the liquid is displaced

C. Viscosity of the liquid

D. Compressibility of the liquid

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4

Liquids

A. Cannot be compressed

B. Occupy definite volume

C. Are not affected by change in pressure and temperature

D. None of the above

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4

According to Newton's law of viscosity, the shear stress on a layer of a fluid is __________ to the rate of shear strain.

A. Equal to

B. Directly proportional

C. Inversely proportional

D. None of these

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4

The surface tension of mercury at normal temperature compared to that of water is

A. More

B. Less

C. Same

D. More or less depending on size of glass tube

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4

Rain drops are spherical because of

A. Viscosity

B. Air resistance

C. Surface tension forces

D. Atmospheric pressure

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4

The discharge through a channel of circular section will be maximum when the depth of water is __________ the diameter of the circular channel.

A. 0.34 times

B. 0.67 times

C. 0.81 times

D. 0.95 times

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4

The weight per unit volume of a liquid at a standard temperature and pressure is called

A. Specific weight

B. Mass density

C. Specific gravity

D. None of these

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4

Poise is the unit of

A. Surface tension

B. Capillarity

C. Viscosity

D. Shear stress in fluids

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4

Surface tension

A. Acts in the plane of the interface normal to any line in the surface

B. Is also known as capillarity

C. Is a function of the curvature of the interface

D. Decreases with fall in temperature

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4

The atmospheric pressure at sea level is

A. 103 kN/m2

B. 10.3 m of water

C. 760 mm of mercury

D. All of these

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4

Falling drops of water become spheres due to the property of

A. Adhesion

B. Cohesion

C. Surface tension

D. Viscosity