F = E - TS
F = H - TS
F = H + TS
F = E + TS
B. F = H - TS
Latent heat of vaporisation
Chemical potential
Molal boiling point
Heat capacity
Volume
Enthalpy
Both (A) & (B)
Neither (A) nor (B)
The values of (∂P/∂V)T and (∂2P/∂V2)T are zero for a real gas at its critical point
Heat transferred is equal to the change in the enthalpy of the system, for a constant pressure, non-flow, mechanically reversible process
Thermal efficiency of a Carnot engine depends upon the properties of the working fluid besides the source & sink temperatures
During a reversible adiabatic process, the entropy of a substance remains constant
Two
One
Zero
Three
Pressure
Temperature
Both (A) & (B)
Neither (A) nor (B)
Surface tension
Free energy
Specific heat
Refractive index
Shifting the equilibrium towards right
Shifting the equilibrium towards left
No change in equilibrium condition
None of these
Zero
One
Infinity
Negative
Does not depend upon temperature
Is independent of pressure only
Is independent of volume only
Is independent of both pressure and volume
Same as Carnot cycle
Same as reverse Carnot cycle
Dependent on the refrigerant's properties
The least efficient of all refrigeration processes
By throttling
By expansion in an engine
At constant pressure
None of these
Adiabatic
Isothermal
Isometric
None of these
2.73
28.3
273
283
First law
Zeroth law
Third law
Second law
Equal to its density
The reciprocal of its density
Proportional to pressure
None of these
dQ = dE + dW
dQ = dE - dW
dE = dQ + dW
dW = dQ + dE
Tds = dE + dW
dE - dW = Tds
dW - dE = Tds
Tds - dW + dE >0
Pressure
Temperature
Both (A) & (B)
Neither (A) nor (B)
Endothermic
Exothermic
Isothermal
Adiabatic
Zero
Unity
Infinity
None of these
V/T = Constant
V ∝ 1/T
V ∝ 1/P
PV/T = Constant
Any
A perfect
An easily liquefiable
A real
Is the most efficient of all refrigeration cycles
Has very low efficiency
Requires relatively large quantities of air to achieve a significant amount of refrigeration
Both (B) and (C)
Increase
Decrease
No change
None of these
0.15
1.5
4.5
6.5
3
4
5
6
Kp2/Kp1 = - (ΔH/R) (1/T2 - 1/T1)
Kp2/Kp1 = (ΔH/R) (1/T2 - 1/T1)
Kp2/Kp1 = ΔH (1/T2 - 1/T1)
Kp2/Kp1 = - (1/R) (1/T2 - 1/T1)
TVγ-1 = constant
p1-γ.TY = constant
PVγ = constant
None of these
448
224
22.4
Data insufficient; can't be computed
Increased COP
Same COP
Decreased COP
Increased or decreased COP; depending upon the type of refrigerant