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**Log _{10} 3+log_{10 }(4x+1)=log_{10 }(x+1)+1**

2/7

7/2

3/7

7/3

B. 7/2

log_{10 }3+log_{10} (4x+1)=log_{10 }(x+1)+1

Log_{10} 3+log_{10} (4x+1)=log_{10 }(x+1)+log_{10} (x+1)+log_{10} 10

Log_{10} (3(4x+1))=log_{10} (10(x+1))

=3(4x+1)=10(x+1)=12x+3

=10x+10

=2x=7=x=7/2