Find the value of x which satisfies the relationLog10 3+log10 (4x+1)=log10 (x+1)+1

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Find the value of x which satisfies the relation

Log₁₀ 3+log₁₀(4x+1)=log₁₀(x+1)+1

A. 2/7

B. 7/2

C. 3/7

D. 7/3

Correct Answer :

B. 7/2

log₁₀3+log₁₀ (4x+1)=log₁₀(x+1)+1

Log₁₀ 3+log₁₀ (4x+1)=log₁₀(x+1)+log₁₀ (x+1)+log₁₀ 10

Log₁₀ (3(4x+1))=log₁₀ (10(x+1))

=3(4x+1)=10(x+1)=12x+3

=10x+10

=2x=7=x=7/2

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