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Find the value of x which satisfies the relation


Log10 3+log10 (4x+1)=log10 (x+1)+1

A. 2/7

B. 7/2

C. 3/7

D. 7/3

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Correct Answer :

B. 7/2


log10 3+log10 (4x+1)=log10 (x+1)+1


Log10 3+log10 (4x+1)=log10 (x+1)+log10 (x+1)+log10 10


Log10 (3(4x+1))=log10 (10(x+1))


=3(4x+1)=10(x+1)=12x+3


=10x+10


=2x=7=x=7/2

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