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If m and n are whole numbers such that $m^{n}$ = 121, the value of $(m - 1)^{n + 1}$ is:

A. 1

B. 10

C. 121

D. 1000

Correct Answer :

D. 1000

We know that

11^{2} = 121 .

Putting m = 11 and n = 2, we get:

(m - 1)^{n + 1} = (11 - 1)^{(2 + 1)} = 10^{3} = 1000 .

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