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If P1 and P2 are the tight and slack side tensions in the belt, then the initial tension Pi (according to Barth) will be equal to

A. [(√P1 + √P2)/2]²

B. P1 + P2

C. 2 × (P1 + P2)

D. [2 × (P1 + P2)] + Pc Where Pc is centrifugal tension

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Correct Answer :

A. [(√P1 + √P2)/2]²


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