Bending moment (i.e. M)
Bending moment² (i.e. M²)
Bending moment³ (i.e. M³)
Bending moment⁴ (i.e. M⁴)
A. Bending moment (i.e. M)
Elastic limit
Yield stress
Ultimate stress
Breaking stress
8/3
11/3
11/7
7/3
d/4
d/8
d/12
d/16
More
Less
Same
More/less depending on composition
Pressure
Volume
Temperature
Density
Inversely proportional to strain
Directly proportional to strain
Square root of strain
Equal to strain
It is impossible to construct an engine working on a cyclic process, whose sole purpose is to convert heat energy into work.
It is impossible to transfer heat from a body at a lower temperature to a higher temperature, without the aid of an external source.
There is a definite amount of mechanical energy, which can be obtained from a given quantity of heat energy.
All of the above
Chain riveted joint
Diamond riveted joint
Crisscross riveted joint
Zigzag riveted joint
Doubled
Halved
Becomes four times
None of the above
3 to 6
5 to 8
15 to 20
20 to 30
Carbon and hydrogen
Oxygen and hydrogen
Sulphur and oxygen
Sulphur and hydrogen
Becomes constant
Starts decreasing
Increases without any increase in load
None of the above
300° to 500°C
500° to 700°C
700° to 900°C
900° to 1100°C
(σx/2) + (1/2) × √(σx² + 4 τ²xy)
(σx/2) - (1/2) × √(σx² + 4 τ²xy)
(σx/2) + (1/2) × √(σx² - 4 τ²xy)
(1/2) × √(σx² + 4 τ²xy)
Breaking stress
Fracture stress
Yield point stress
Ultimate tensile stress
Extensive heat is transferred
Extensive work is done
Extensive energy is utilised
None of these
The product of the gas constant and the molecular mass of an ideal gas is constant
The sum of partial pressure of the mixture of two gases is sum of the two
Equal volumes of all gases, at the same temperature and pressure, contain equal number of molecules
All of the above
Gas engine
Petrol engine
Steam engine
Reversible engine
Two constant volume and two isentropic processes
Two constant pressure and two isentropic processes
Two constant volume and two isothermal processes
One constant pressure, one constant volume and two isentropic processes
Same
Double
Half
One-fourth
l/δl
δl/l
l.δl
l + δl
Temperature limits
Pressure ratio
Volume compression ratio
Cut-off ratio and compression ratio
0.01 to 0.1
0.23 to 0.27
0.25 to 0.33
0.4 to 0.6
One
Two
Three
Four
It does not exist
It is more sensitive to changes in both metallurgical and mechanical conditions
It gives a more accurate picture of the ductility
It can be correlated with stress strain values in other tests like torsion, impact, combined stress tests etc.
Specific heat at constant volume
Specific heat at constant pressure
kilo-Joule
None of these
0
1
γ
∝
Yield point
Limit of proportionality
Breaking point
Elastic limit
For a given compression ratio, both Otto and Diesel cycles have the same efficiency.
For a given compression ratio, Otto cycle is more efficient than Diesel cycle.
For a given compression ratio, Diesel cycle is more efficient than Otto cycle.
The efficiency of Otto or Diesel cycle has nothing to do with compression ratio.
Rubber
Plastic
Brass
Steel