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In a totally irreversible isothermal expansion process for an ideal gas, ΔE = 0, ΔH = 0. Then ΔQ and ΔS will be

A. ΔQ = 0, ΔS=0

B. ΔQ = 0, ΔS = +ve

C. ΔQ = 0, ΔS = -ve

D. ΔQ = +ve, ΔS= +ve

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Correct Answer : B.


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