Mechanical advantage is greater than velocity ratio
Mechanical advantage is equal to velocity ratio
Mechanical advantage is less than velocity ratio
Mechanical advantage is unity
C. Mechanical advantage is less than velocity ratio
IP = IG + Ah2
IP = IG - Ah2
IP = IG / Ah2
IP = Ah2 / IG
Downwards at its upper end
Upwards at its upper end
Perpendicular to the wall at its upper end
Zero at its upper end
πd3/16
πd3/32
πd4/32
πd4/64
P/sin β = Q/sin α = R/sin
P/sin α = Q/sin β = R/sin
P/sin = Q/sin α = R/sin β
P/sin α = Q/sin = R/sin β
Less than
Greater than
Equal to
None of these
P + m.a = 0
P - m.a = 0
P × m.a = 0
P/m.a = 0
At distance from the plane base 3r
At distance from the plane base 3r
At distance from the plane base 3r
At distance from the plane base
Downward at its upper end
Upward at its upper end
Zero at its upper end
Perpendicular to the wall at its upper end
The kinetic energy of a body during impact remains constant.
The kinetic energy of a body before impact is equal to the kinetic energy of a body after impact.
The kinetic energy of a body before impact is less than the kinetic energy of a body after impact.
The kinetic energy of a body before impact is more than the kinetic energy of a body after impact.
W sinθ
W cosθ
W secθ
W cosecθ
Is the turning effect produced by a force, on the body, on which it acts
Is equal to the product of force acting on the body and the perpendicular distance of a point and the line of action of the force
Is equal to twice the area of the triangle, whose base is the line representing the force and whose vertex is the point, about which the moment is taken
All of the above
Half
Equal to
Double
None of these
ω/r
ω.r
ω2/r
ω2.r
Impulsive force
Mass
Weight
Momentum
Along the plane
Horizontally
Vertically
At an angle equal to the angle of friction to the inclined plane
Rotate about itself without moving
Move in any one direction rotating about itself
Be completely at rest
All of these
Algebraic sum of the horizontal components of all the forces should be zero
Algebraic sum of the vertical components of all the forces should be zero
Algebraic sum of moments of all the forces about any point should be zero
All of the above
W sinθ
W cosθ
W tanθ
W cotθ
Three forces acting at a point will be in equilibrium
Three forces acting at a point can be represented by a triangle, each side being proportional to force
If three forces acting upon a particle are represented in magnitude and direction by the sides of a triangle, taken in order, they will be in equilibrium
If three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two
25
50
100
250
Meet
Do not meet
Either A or B
None of these
Three forces acting at a point will be in equilibrium
Three forces acting at a point can be represented by a triangle, each side being proportional to force
If three forces acting upon a particle are represented in magnitude and direction by the sides of a triangle, taken in order, they will be in equilibrium
If three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two
Directly
Inversely
Square root
None of these
20 kg, -ve sense
20 kg, + ve sense
10 kg, + ve sense
10 kg, -ve sense
Kinetic friction
Limiting friction
Angle of repose
Coefficient of friction
v = u + a.t
s = u.t + ½ a.t2
v2 = u2 + 2a.s
All of these
P = mW - C
P = m/W + C
P = mW + C
P = C - mW
Magnitude of the force
Line of action of the force
Nature of the force i.e. whether the force is push or pull
All of the above
π/16 (D² - d²)
π/16 (D³ - d³)
π/32 (D⁴ - d⁴)
π/64 (D⁴ - d⁴)
0° and 180°
180° and 0°
90° and 180°
90° and 0°