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$P C L_{5}$ is kept in a closed container at a temperature of 250 K the equilibrium concentration of the different substances is $[P C L_{5}] = 0.045 m o l e s l i t e r^{- 1} [P C L_{3}] = [C L_{2}] = 0.096 m o l e s l i t e r^{- 1}$ The value of equilibrium constant for the reaction $P C L_{5} ⇋ P C L_{3} + C L_{2}$ will be

A. 50

B. 50.4

C. 0.0205

D. 0.205

Correct Answer :

C. 0.0205

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