"[]" Operator is a unary operator.
True
False
Correct Answer :
A. True
Related Questions
cc ___________ option is used only to create object file
-a
-o
-c
none of these
"[]" Operator is a unary operator.
True
False
The following syntax is valid. void inline gram_ panchayat :: show_gram_ panchayat_info().
True
False
The members of a class by default are private.
True
False
By default, C++ uses the following method of passing arguments
Call-by-Reference
Call-by-Value
Call-by-Pointer
None of the above
In C++, identifiers have to be declared at the beginning of the blocks.
True
False
A member function can always access the data
In the object of which it is a member
In the class of which it is a member
In the object of the class of which it is a member
In the public part of its class
Which of the following is true about const member functions?
const members can be invoked on both const as well as nonconst objects
const members can be invoked only on const objects and not on nonconst objects
nonconst members can be invoked on const objects as well as nonconst objects
none of the above
The binding that binds a function call at run time is called
early binding
run time binding
late binding
linking
Pick out the most appropriate statement from the following
references are pointers
array of references can be created
you can not reference a reference variable
all of the above
One of the major disadvantage with late binding is
the source code should be made available at compile time
the program runs slower
dynamic variables can not be used in the program
static variables can not be used
Protected data members can be accessed
Only from the base class itself
Both form the base class and from its derived classes
From the class which is friend of the base class
None of the above are correct
Which of the following can legitimately be passed to a function?
A constant
A variable
A structure
A header file
An object is an allocated space in memory.
True
False
Sharing of common information are achieved by the concept of
Virtual copying
Inheritance
Encapsulation
None of these
Friend function have access to the
private and protected members
public members only
private members only
None of the above are correct
A destructor can have arguments like constructor.
True
False
If class A is friend of class B and if class B is friend of class C, which of the following is true?
Class C is friend of class A
Class A is friend of class C
Class A and Class C do not have any friend relationship
None of the above
Which of the following are good reasons to use an object oriented language?
You can define your data types
Program statements are simpler than in procedural languages.
An OO program can be taught to correct its own errors.
It's easier to conceptualize an OO program.
A variable defined within a block is visible
From the point of definition onwards in the program
From the point of definition onwards in the function
From the point of definition onwards in the block
Throughout the function
By using protected, one can create class members that are private to their class but
that can not be inherited and accessed by a derived class
that can still be inherited and accessed by a derived class
that can be public
none of the above
We cannot have the address of a constructor.
True
False
Inline functions_____________ call overload.
Increase
Reduce
None of the above are correct
Operator overloading is
Making C++ operators work with objects
Making C++ operators more then they can handle
Giving new meaning to existing c++ operators
Making new C++ operators
Organizing data with methods that operate on the data and creating a new data type is called encapsulation.
True
False
What is the output of the following program segment - for(i = 1, j = 0; i < 10; i++) j += i; cout <<i<<"
";
10
20
55
there is an error in the program
Static member functions have file scope.
True
False
The string table in C++ holds the
string constants in your program
program statements in string form
variables whose type is of string
none of the above
You can read input that consists of multiple lines of text using
The normal cout<< combination
The cin.get() function with one argument
The cin.get() function with two argument
The cin.get() function with three argument
The signature of a function is
The return type
The number and type of arguments
The class of a function
None of the above