An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30º. The heights of the tower is:
A. 21.6 m
B. 23.2 m
C. 24.72 m
D. None of these
Let AB be the observer and CD be the tower.
Draw BE CD.
Then, CE = AB = 1.6 m,BE=AC=203mDEBE=tan 30º=13⇒DE=2033m=20m CD = CE + DE = (1.6 + 20) m = 21.6 m.
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