A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type.

Question

A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type.

A. 50p coins=200,25p coins=360,10p coins=160

B. 50p coins=200,25p coins=400,10p coins=120

C. 50p coins=240,25p coins=360,10p coins=120

D. 50p coins=205,25p coins=365,10p coins=150

Let the number of 50 p, 25 P and 10 p coins be 5x, 9x and 4x respectively.
(5x/2)+( 9x/ 4)+(4x/10)=206
⇔ 50x + 45x + 8x = 4120
⇔1O3x = 4120
⇔x=40.

Number of 50 p coins = (5 x 40) = 200;
Number of 25 p coins = (9 x 40) = 360;
Number of 10 p coins = (4 x 40) = 160.

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Accepted Answer

A. 50p coins=200,25p coins=360,10p coins=160

A bag contains 50 p, 25 P and 10 p coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type.

Correct Answer :

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