100 hrs

122 hrs

177 hrs

112 hrs

D. 112 hrs

Work done by the two pipes in 1 hour =(1/14)+(1/16)=(15/112).

Time taken by these pipes to fill the tank = (112/15) hrs = 7 hrs 28 min.

Due to leakage, time taken = 7 hrs 28 min + 32 min = 8 hrs

Work done by (two pipes + leak) in 1 hour = (1/8).

Work done by the leak m 1 hour =(15/112)-(1/8)=(1/112).

Leak will empty the full cistern in 112 hours.

10 min

20 min

40 min

50 min

18 hrs

13 hrs

20 hrs

23 hrs

39 min

40 min

50 min

45min

100 hrs

122 hrs

177 hrs

112 hrs

20 hrs

23 hrs

30 hrs

21 hrs

7 hrs

7 hrs 30 min

5 hrs

5 hrs 30 min