100 hrs
122 hrs
177 hrs
112 hrs
D. 112 hrs
Work done by the two pipes in 1 hour =(1/14)+(1/16)=(15/112).
Time taken by these pipes to fill the tank = (112/15) hrs = 7 hrs 28 min.
Due to leakage, time taken = 7 hrs 28 min + 32 min = 8 hrs
Work done by (two pipes + leak) in 1 hour = (1/8).
Work done by the leak m 1 hour =(15/112)-(1/8)=(1/112).
Leak will empty the full cistern in 112 hours.
39 min
40 min
50 min
45min
10 min
20 min
40 min
50 min
18 hrs
13 hrs
20 hrs
23 hrs
7 hrs
7 hrs 30 min
5 hrs
5 hrs 30 min
20 hrs
23 hrs
30 hrs
21 hrs
100 hrs
122 hrs
177 hrs
112 hrs