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What is the correct answer?

4

What will be output if you will compile and execute the following c code?


#include 
#define x 5+2
int main(){
int i;
i=x*x*x;
printf("%d",i);
return 0;
}


A. 27

B. 343

C. 233

D. Compiler Error

Correct Answer :

A. 27


As we know #define is token pasting preprocessor it only paste the value of micro constant in the program before the actual compilation start. If you will see intermediate file you will find:
test.c 1: 
test.c 2: void main(){
test.c 3: int i;
test.c 4: i=5+2*5+2*5+2;
test.c 5: printf("%d",i); 
test.c 6: }
test.c 7: 


You can absorb #define only pastes the 5+2 in place of x in program. So, i=5+2*5+2*5+2


=5+10+10+2


=27

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int f(int a, int b); 
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