A conical vessel, whose internal radius is 12 cm and height 50 cm, is full of liquid. The contents are emptied into a cylindrical vessel with internal radius 10 cm. Find the eight to which the liquid rises in the cylindrical vessel.

Volume of the liquid in the cylindrical vessel = Volume of the conical vessel

                      = ((1/3)* (22/7)* 12 * 12 * 50) )cm³ = (22 *4 *12 * 50)/7 cm³.

Let the height of the liquid in the vessel be h.

Then (22/7)*10*10*h =(22*4*12*50)/7 or h = (4*12*50)/100 = 24 cm