Find the largest number of four digits exactly divisible by 12,15,18 and 27.

The Largest number of four digits is 9999.

       Required number must be divisible by L.C.M. of 12,15,18,27 i= 540.

       On dividing 9999 by 540,we get 279 as remainder .

        Required number = (9999-279) = 9720.