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Find the largest number of four digits exactly divisible by 12,15,18 and 27.

A. 9999

B. 9988

C. 9872

D. 9720

Correct Answer :

D. 9720


The Largest number of four digits is 9999.


       Required number must be divisible by L.C.M. of 12,15,18,27 i= 540.


       On dividing 9999 by 540,we get 279 as remainder .


        Required number = (9999-279) = 9720.

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