Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder .

Correct Answer : A.

   L.C.M. of 5,6,7,8 = 840.

   Required number is of the form 840k + 3

   Least value of k for which (840k + 3) is divisible by 9 is k = 2.

   Required number = (840 X 2 + 3)=1683