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Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder .

A. 1683

B. 1892

C. 1762

D. 1823

Correct Answer : A.


   L.C.M. of 5,6,7,8 = 840.


   Required number is of the form 840k + 3


   Least value of k for which (840k + 3) is divisible by 9 is k = 2.


   Required number = (840 X 2 + 3)=1683

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