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What is the correct answer?

4

The centre of gravity of the trapezium as shown in below figure from the side is at a distance of

A. (h/3) × [(b + 2a)/(b + a)]

B. (h/3) × [(2b + a)/(b + a)]

C. (h/2) × [(b + 2a)/(b + a)]

D. (h/2) × [(2b + a)/(b + a)]