Output to the input
Work done by the machine to the work done on the machine
Mechanical advantage to the velocity ratio
All of the above
D. All of the above
tanθ = ΣH/ΣV
tanθ = ΣV/ΣH
tanθ = ΣV × ΣH
tanθ = √(ΣV + ΣH)
Equal to the moment of the couple
Constant
Both of above are correct
Both of above are wrong
Strain energy
Kinetic energy
Heat energy
Electrical energy
Reversible machine
Non-reversible machine
Neither reversible nor non-reversible machine
Ideal machine
The three forces must be equal
The three forces must be at 120° to each other
The three forces must be in equilibrium
If the three forces acting at a point are in equilibrium, then each force is proportional to the sine of the angle between the other two
Will
Will not
Either A or B
None of these
g. cos² β/2u². sin (α + β). cos α
2u². sin (α + β). cos α/g. cos² β
g. cos² β/2u². sin (α - β). cos α
2u². sin (α - β). cos α/g. cos² β
Algebraic sum of the horizontal components of all the forces should be zero
Algebraic sum of the vertical components of all the forces should be zero
Algebraic sum of moments of all the forces about any point should be zero
All of the above
W sinθ
W cosθ
W secθ
W cosecθ
Kinetic friction
Limiting friction
Angle of repose
Coefficient of friction
Magnitude
Direction
Position or line of action
All of the above
Newton
Pascal
Watt
Joule
Two times
Same
Half
None of these
Friction
Limiting friction
Repose
Kinematic friction
One-fourth of the total height above base
One-third of the total height above base
One-half of the total height above base
Three-eighth of the total height above the base
Energy
Mass
Momentum
Angle
Linear displacement
Linear velocity
Linear acceleration
All of these
g (m1 - m2)/(m1 + m2)
2g (m1 - m2)/(m1 + m2)
g (m1 + m2)/(m1 - m2)
2g (m1 + m2)/(m1 - m2)
(2/3) Ml2
(1/3) Ml2
(3/4) Ml2
(1/12) Ml2
5
10
20
40
Is the turning effect produced by a force, on the body, on which it acts
Is equal to the product of force acting on the body and the perpendicular distance of a point and the line of action of the force
Is equal to twice the area of the triangle, whose base is the line representing the force and whose vertex is the point, about which the moment is taken
All of the above
Three forces acting at a point will be in equilibrium
Three forces acting at a point can be represented by a triangle, each side being proportional to force
If three forces acting upon a particle are represented in magnitude and direction by the sides of a triangle, taken in order, they will be in equilibrium
If three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two
0.1 N-m
1 N-m
10 N-m
100 N-m
(BD³/12) - (bd³/12)
(DB³/12) - (db³/12)
(BD³/36) - (bd³/36)
(DB³/36) - (db³/36)
2n³
2n
n²
3n² Where n = number of joints in a frame
Less than
More than
Equal to
None of These
1/2
2/3
3/2
2/4
Halved
Doubled
Quadrupled
None of these
m₁. m₂. g/(m₁ + m₂)
2m₁. m₂. g/(m₁ + m₂)
(m₁ + m₂)/ m₁. m₂. g
(m₁ + m₂)/2m₁. m₂. g
Resultant couple
Moment of the forces
Resulting couple
Moment of the couple