# The equilibrium constant for the reaction at 523 K $PC{L}_{5}\left(g\right)⇌PC{L}_{3}\left(g\right)+C{L}_{2}\left(g\right)$ is0.04. If value of R = 8.314 $J{K}^{-1}$ then $∆G°$ for the reaction will be

0.13

5

+13.9 kj

-13.9 kj

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