2400 sq.cm

2480 sq.cm

2560 sq.cm

None of these

C. 2560 sq.cm

$Letbreadth=xcm.Then,length=\left(\frac{160}{100}x\right)cm=\frac{8}{5}xcm\phantom{\rule{0ex}{0ex}}So,\frac{8}{5}x-x=24\phantom{\rule{0ex}{0ex}}\frac{3}{5}x=24\phantom{\rule{0ex}{0ex}}x=\left(\frac{24\times 5}{3}\right)=40\phantom{\rule{0ex}{0ex}}\therefore Length=64cm,Breadth=40cm\phantom{\rule{0ex}{0ex}}Area=\left(64\times 40\right)c{m}^{2}=2560c{m}^{2}$