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40 m

50 m

120 m

None of these

D. None of these

$Letbreadth=xmetres.Then,length=(x+20)m\phantom{\rule{0ex}{0ex}}Perimeter=\left(\frac{5300}{26.50}\right)m=200m\phantom{\rule{0ex}{0ex}}\therefore 2\left[\left(x+20\right)+x\right]=200,2x+20=100,2x=80,x=40\phantom{\rule{0ex}{0ex}}Hence,length=x+20=40+20=60m$