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What is the correct answer?

4

The logarithmic mean temperature difference (tm) is given by (where Δt1 and Δt2 are temperature differences between the hot and cold fluids at entrance and exit)

A. tm = (Δt1 - Δt2)/ loge (Δt1/Δt2)

B. tm = loge (Δt1/Δt2)/ (Δt1 - Δt2)

C. tm = tm = (Δt1 - Δt2) loge (Δt1/Δt2)

D. tm = loge (Δt1 - Δt2)/ Δt1/Δt2

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