Chemical potentials of a given component should be equal in all phases
Chemical potentials of all components should be same in a particular phase
Sum of the chemical potentials of any given component in all the phases should be the same
None of these
A. Chemical potentials of a given component should be equal in all phases
0°C and 750 mm Hg
15°C and 750 mm Hg
0°C and 1 kgf/cm2
15°C and 1 kgf/cm2
Decreases
Increases
Remains constant
Decreases logarithmically
Ethyl chloride or methyl chloride
Freon-12
Propane
NH3 or CO2
CO2
H2
O2
N2
Only enthalpy change (ΔH) is negative
Only internal energy change (ΔE) is negative
Both ΔH and ΔE are negative
Enthalpy change is zero
Minimum temperature attainable
Temperature of the heat reservoir to which a Carnot engine rejects all the heat that is taken in
Temperature of the heat reservoir to which a Carnot engine rejects no heat
None of these
Δ S1 is always < Δ SR
Δ S1 is sometimes > Δ SR
Δ S1 is always > Δ SR
Δ S1 is always = Δ SR
Entropy
Internal energy
Enthalpy
Gibbs free energy
Internal energy
Enthalpy
Entropy
All (A), (B) & (C)
Enthalpy
Volume
Both 'a' & 'b'
Neither 'a' nor 'b'
Enthalpy
Pressure
Entropy
None of these
Bertholet equation
Clausius-Clapeyron equation
Beattie-Bridgeman equation
None of these
Molar volume, density, viscosity and boiling point
Refractive index and surface tension
Both (A) and (B)
None of these
2HI H2 + I2
N2O4 2NO2
2SO2 + O2 2SO3
None of these
Zero
Negative
Very large compared to that for endothermic reaction
Not possible to predict
Oxygen
Nitrogen
Air
Hydrogen
Is increasing
Is decreasing
Remain constant
Data insufficient, can't be predicted
Water
Air
Evaporative
Gas
Low pressure and high temperature
Low pressure and low temperature
Low temperature and high pressure
High temperature and high pressure
Trouton's ratio of non-polar liquids is calculated using Kistyakowsky equation
Thermal efficiency of a Carnot engine is always less than 1
An equation relating pressure, volume and temperature of a gas is called ideal gas equation
None of these
Is zero
Increases
Decreases whereas the entropy increases
And entropy both decrease
Kp2/Kp1 = - (ΔH/R) (1/T2 - 1/T1)
Kp2/Kp1 = (ΔH/R) (1/T2 - 1/T1)
Kp2/Kp1 = ΔH (1/T2 - 1/T1)
Kp2/Kp1 = - (1/R) (1/T2 - 1/T1)
Low T, low P
High T, high P
Low T, high P
High T, low P
Temperature
Mass
Volume
Pressure
Bomb
Separating
Bucket
Throttling
Positive
Negative
Zero
Infinity
Work required to refrigeration obtained
Refrigeration obtained to the work required
Lower to higher temperature
Higher to lower temperature
0
1
2
3
Henry's law
Law of mass action
Hess's law
None of these
Ideal
Very high pressure
Very low temperature
All of the above