4

# The perimeters of 5 squares are 24 cm, 32 cm, 40 cm, 76 cm and 80 cm respectively. The perimeter of another square equal in area to the sum of the area of these square is

50 cm

64 cm

124 cm

120 cm

C. 124 cm

Clearly first we need to find the areas of the given squares, for that we need its side.
Side of sqaure = Perimeter/4
So sides are,

4

20000

23000

25000

26000

4

7 cm

7.1 cm

7.2 cm

7.3 cm

4

55 m

56 m

57 m

58 m

4

46 sq.ft

81 sq.ft

126 sq.ft

252 sq.ft

4

614

714

814

914

4

# The diffrence between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m,then its area is:

1520 ${m}^{2}$

2420 ${m}^{2}$

2480 ${m}^{2}$

2520 ${m}^{2}$

4

18750 sq.m

37500 sq.m

40000 sq.m

48000 sq.m

4

110 cm

115 cm

120 cm

125 cm

4

2400 sq.cm

2480 sq.cm

2560 sq.cm

None of these

4

# The Diagonals of two squares are in the ratio of 2:5. find the ratio of their areas.

$4:15$

$4:25$

$3:15$

$3:25$

4

# The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is

$44%$

$45%$

$34%$

$35%$

4

15,000

15,500

15,600

16,500

4

40 m

50 m

120 m

None of these

4

200cm

150cm

180cm

100cm

4

4

4

3410

3420

3430

3440

4

50 cm

64 cm

124 cm

120 cm

4

4

# The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is

$153500{m}^{2}$

$152500{m}^{2}$

$153800{m}^{2}$

$153600{m}^{2}$

4