50 cm

64 cm

124 cm

120 cm

C. 124 cm

Clearly first we need to find the areas of the given squares, for that we need its side.

Side of sqaure = Perimeter/4

So sides are,

$\left(\frac{24}{4}\right),\left(\frac{32}{4}\right),\left(\frac{40}{4}\right),\left(\frac{76}{4}\right),\left(\frac{80}{4}\right)\phantom{\rule{0ex}{0ex}}=6,8,10,19,20\phantom{\rule{0ex}{0ex}}Areaofnewsquarewillbe\phantom{\rule{0ex}{0ex}}=\left[{6}^{2}+{8}^{2}+{10}^{2}+{19}^{2}+{20}^{2}\right]\phantom{\rule{0ex}{0ex}}=36+64+100+361+400\phantom{\rule{0ex}{0ex}}=961c{m}^{2}\phantom{\rule{0ex}{0ex}}SideofnewSqaure=\sqrt{961}\phantom{\rule{0ex}{0ex}}=31cm\phantom{\rule{0ex}{0ex}}Requiredperimeter=\left(4\times 31\right)\phantom{\rule{0ex}{0ex}}=124cm\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$