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The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares .

A. 24 cm

B. 26 cm

C. 23 cm

D. 28 cm

Correct Answer : A.


We know perimeter of square = 4(side)
So Side of first square = 40/4 = 10 cm
Side of second square = 32/4 = 8 cm
Area of third Square = 10*10 - 8*8
= 36 cm
So side of third square = 6 (because area of square = side*side)
Perimeter=4*Side=4*6=24 cm

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