The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares .

A. $24 c m$

B. $26 c m$

C. $23 c m$

D. $28 c m$

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Correct Answer : A.

We know perimeter of square = 4(side)
So Side of first square = 40/4 = 10 cm
Side of second square = 32/4 = 8 cm
Area of third Square = 10*10 - 8*8
= 36 cm
So side of third square = 6 (because area of square = side*side)

P e r i m e t e r = 4 * S i d e = 4 * 6 = 24 c m

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