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10

8

4

None

A. 10

Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12. We know that the sum of their ages is 50 . so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50 inline Rightarrow x= 4 inline herefore The youngest child is 4 years old.