Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?

Question

Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?

A. $\frac{1}{3}$

B. $\frac{1}{6}$

C. $\frac{1}{2}$

D. $\frac{1}{8}$

Total cases are = 2*2*2 = 8, which are as follows
[TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]
Favoured cases are = [TTH, THT, HTT, TTT] = 4
So required probability =

\frac{4}{8} = \frac{1}{2}

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Accepted Answer

C.

\frac{1}{2}

Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?

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