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# Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?

$\frac{1}{3}$

$\frac{1}{6}$

$\frac{1}{2}$

$\frac{1}{8}$

C. $\frac{1}{2}$
So required probability =$\frac{4}{8}=\frac{1}{2}$