$\frac{3}{4}$

$\frac{1}{4}$

$\frac{7}{4}$

$\frac{1}{2}$

A. $\frac{3}{4}$

Total number of cases =$6\times 6=36$

Favourable cases = [(1,2),(1,4),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,2),(3,4),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,2),(5,4),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)] = 27

So Probability =$\frac{27}{36}=\frac{3}{4}$