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50 m

72 m

80 m

82 m

A. 50 m

$Letthelengthofeachtrainbexmetres.\phantom{\rule{0ex}{0ex}}Then,dis\mathrm{tan}cecovered=2xmetres.\phantom{\rule{0ex}{0ex}}Relativespeed=(46-36)km/hr\phantom{\rule{0ex}{0ex}}=\left(10x\frac{5}{18}\right)m/sec\phantom{\rule{0ex}{0ex}}=\left(\frac{25}{9}\right)m/sec\phantom{\rule{0ex}{0ex}}\therefore \frac{2x}{36}=\frac{25}{9}\phantom{\rule{0ex}{0ex}}\Rightarrow 2x=100\phantom{\rule{0ex}{0ex}}\Rightarrow x=50.$