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Two unbiased coins are tossed. What is probability of getting at most one tail ?

A. $\frac{1}{2}$

B. $\frac{1}{3}$

C. $\frac{3}{2}$

D. $\frac{3}{4}$

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Correct Answer : D.

Total 4 cases = [HH, TT, TH, HT]
Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.
So probability =

\frac{3}{4}

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