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# What is the probability of getting a sum 9 from two throws of dice.

$\frac{1}{3}$

$\frac{1}{9}$

$\frac{1}{12}$

$\frac{2}{9}$

B. $\frac{1}{9}$
So probability = $\frac{4}{36}=\frac{1}{9}$