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What is the probability of getting a sum 9 from two throws of dice.

A. $\frac{1}{3}$

B. $\frac{1}{9}$

C. $\frac{1}{12}$

D. $\frac{2}{9}$

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Correct Answer :

B. $\frac{1}{9}$

Total number of cases = 6*6 = 36
Favoured cases = [(3,6), (4,5), (6,3), (5,4)] = 4
So probability =

\frac{4}{36} = \frac{1}{9}

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