Gibbs-Duhem equation
Gibbs-Helmholtz equation
Third law of thermodynamics
Joule-Thomson effect
D. Joule-Thomson effect
Freezing
Triple
Boiling
Boyle
Air compressor
Liquid cooling system of an automobile
Boiler
None of these
Isothermal
Adiabatic
Both (A) & (B)
Neither (A) nor (B)
Isobaric
Isothermal
Adiabatic
None of these
Mass
Energy
Momentum
None of these
Heat capacity
Molal heat capacity
Pressure
Concentration
F = A + PV
F = E + A
F = A - TS
F = A + TS
Expansion of a real gas
Reversible isothermal volume change
Heating of an ideal gas
Cooling of a real gas
5 & 3
3.987 & 1.987
1.987 & 0.66
0.66 & 1.987
(dF)T, p < 0
(dF)T, p > 0
(dF)T, p = 0
(dA)T, v < 0
Zero
+ve
-ve
Dependent on the path
It is exothermic
It is isenthalpic
It takes place isothermally
It takes place at constant volume
Specific heat at constant pressure (Cp)
Specific heat at constant volume (Cv)
Joule-Thompson co-efficient
None of these
0°C
273°C
100°C
-273°C
0°C and 750 mm Hg
15°C and 750 mm Hg
0°C and 1 kgf/cm2
15°C and 1 kgf/cm2
Decreases
Increases
Remains constant
Decreases logarithmically
Sublimation
Vaporisation
Melting
Either (A), (B) or (C)
Value of absolute entropy
Energy transfer
Direction of energy transfer
None of these
Kp2/Kp1 = - (ΔH/R) (1/T2 - 1/T1)
Kp2/Kp1 = (ΔH/R) (1/T2 - 1/T1)
Kp2/Kp1 = ΔH (1/T2 - 1/T1)
Kp2/Kp1 = - (1/R) (1/T2 - 1/T1)
ds = 0
ds <0
ds > 0
ds = Constant
P + F - C = 2
C = P - F + 2
F = C - P - 2
P = F - C - 2
5.2
6.2
0.168
Data insufficient, can't be found out
Enthalpy does not remain constant
Entire apparatus is exposed to surroundings
Temperature remains constant
None of these
Reversible isothermal
Irreversible isothermal
Reversible adiabatic
None of these
0°C and 760 mm Hg
15°C and 760 mm Hg
20°C and 760 mm Hg
0°C and 1 kgf/cm2
Extensive property
Intensive property
Force which drives the chemical system to equilibrium
Both (B) and (C)
Air cycle
Carnot cycle
Ordinary vapour compression cycle
Vapour compression with a reversible expansion engine
Pressure
Volume
Mass
None of these
Doubling the absolute temperature as well as pressure of the gas
Reducing pressure to one fourth at constant temperature
Reducing temperature to one fourth at constant pressure
Reducing the temperature to half and doubling the pressure
T = [RT/(V- b)] - [a/√T. V(V + b)]
PV/RT = 1 + (B/V) + (C/V2) + ……
n1u2 + μ2μ1 = 0
None of these