When the belt is transmitting maximum power, the belt speed should be
√(Pmax / 2m)
√(Pmax / 3m)
√(Pmax / m)
√(3m /Pmax) Where m = mass of belt per metre (kg/m) Pmax = maximum permissible tension in belt (N)
Correct Answer :
B. √(Pmax / 3m)
Related Questions
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Elastic limit to the yield point
Endurance limit to the working stress
Young's modulus to the ultimate tensile strength
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Remain same
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Brittle materials
Non-ferrous materials
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Is uniform throughout
Varies exponentially, being more near the torque-input end
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Worm gearing
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Lower surface
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