Proportional limit, elastic limit, yielding, failure
Elastic limit, proportional limit, yielding, failure
Yielding, proportional limit, elastic limit, failure
None of the above
A. Proportional limit, elastic limit, yielding, failure
(23/100) × Mass of excess carbon
(23/100) × Mass of excess oxygen
(100/23) × Mass of excess carbon
(100/23) × Mass of excess oxygen
Enthalpy
Internal energy
Entropy
External energy
In the middle
At the tip below the load
At the support
Anywhere
Boyle's law
Charles' law
Gay-Lussac law
Avogadro's law
Volume
Temperature
Mass
Energy
Very low
Low
High
Very high
(p2/p1)γ - 1/ γ
(p1/p2)γ - 1/ γ
(v2/v1)γ - 1/ γ
(v1/v2)γ - 1/ γ
Kh > Ks
Kh < Ks
Kh = Ks
None of these
Oxygen
Sulphur
Nitrogen
Carbon
30 kJ
54 kJ
84 kJ
114 kJ
Change
Do not change
Both (A) and (B)
None of these
Equal to
Directly proportional to
Inversely proportional to
Independent of
2/3
3/4
1
9/8
Permanent
Temporary
Semi-permanent
None of these
It is possible to transfer heat from a body at a lower temperature to a body at a higher temperature.
It is impossible to transfer heat from a body at a lower temperature to a body at a higher temperature, without the aid of an external source.
It is possible to transfer heat from a body at a lower temperature to a body at a higher temperature by using refrigeration cycle.
None of the above
Strain energy
Resilience
Proof resilience
Modulus of resilience
Temperature limits
Pressure ratio
Compression ratio
Cut-off ratio and compression ratio
Long
Medium
Short
None of these
0.287 J/kgK
2.87 J/kgK
28.7 J/kgK
287 J/kgK
Bearing stresses
Fatigue stresses
Crushing stresses
Resultant stresses
1 kg of water
7 kg of water
8 kg of water
9 kg of water
There is no change in temperature
There is no change in enthalpy
There is no change in internal energy
All of these
0
1
γ
∝
Increase
Decrease
Remain same
Increase initially and then decrease
Carbon and hydrogen
Oxygen and hydrogen
Sulphur and oxygen
Sulphur and hydrogen
Butt joint
Lap joint
Double riveted lap joints
All types of joints
For a given compression ratio, both Otto and Diesel cycles have the same efficiency.
For a given compression ratio, Otto cycle is more efficient than Diesel cycle.
For a given compression ratio, Diesel cycle is more efficient than Otto cycle.
The efficiency of Otto or Diesel cycle has nothing to do with compression ratio.
Same
Double
Half
Four times
(p - 2d) t × σc
(p - d) t × τ
(p - d) t × σt
(2p - d) t × σt
11/7
9/7
4/7
All of the above