Simple Interest MCQ Question with Answer

         Time = (24+31+18)days = 73 days = 73/365 years = 1/5 years.

         P = Rs.3000 and R = 6 ¼ %p.a = 25/4%p.a

         S.I. = Rs.(3,000*(25/4)*(1/5)*(1/100))= Rs.37.50.

Let sum be Rs. x then , S.I.=Rs.(x*(27/2) *4*(1/100) ) = Rs.27x/50

       amount = (Rs. x+(27x/50)) = Rs.77x/50

        77x/50 = 2502.50
       
        x =$\frac{2502.50*50}{77}$   = 1625                                                 

         Hence , sum = Rs.1625.

 P = Rs.68000,R = 50/3% p.a and T = 9/12 years = 3/4years.

 S.I. = (P*R*T)/100 = Rs.(68,000*(50/3)*(3/4)*(1/100))= Rs.8500

S.l. = Rs. (920 - 800) = Rs. 120; p = Rs. 800, T = 3 yrs. _

      R = {(100 * 120)/(800*3)} % = 5%.

       New rate = (5 + 3)% = 8%.

       New S.l. = Rs. (800*8*3)/100 = Rs. 192.

        New amount = Rs.(800+192) = Rs. 992.

(x*2*6)/100 + (x*9*3)/100 + (x*14*4)/100 = 11400

 (3x/25 + 27x/100 + 14x / 25) = 11400     
 95x/100 = 11400 ,
 x = (11400*100)/95 = 12000.

Hence , sum borrowed = Rs.12,000.