According to Bazin's formula, the discharge over a rectangular weir is mL2g x H3/2where m is equal to
0.405 + (0.003/H)
0.003 + (0.405/H)
0.405 + (H/0.003)
0.003 + (H/0.405)
Correct Answer :
A. 0.405 + (0.003/H)
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