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According to Bazin's formula, the discharge over a rectangular weir is mL2g x H3/2where m is equal to

A. 0.405 + (0.003/H)

B. 0.003 + (0.405/H)

C. 0.405 + (H/0.003)

D. 0.003 + (H/0.405)

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Correct Answer : A.


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