Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is ?

A. 1:3

B. 3:2

C. 3:5

D. 3:7

Share this question with your friends

Correct Answer : B.

Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
Length of the second train = 17y metres.
[because distance = speed*time]

\frac{27 x + 17 y}{x + y} = 23 \Rightarrow 27 x = 17 y = 23 x + 23 y \Rightarrow 4 x = 6 y \Rightarrow \frac{x}{y} = \frac{6}{4}

So ratio of the speeds of train is 3:2

Comment

Also checkout

Phylum - Echinodermata MCQ Coding Decoding MCQ Auto CAD 2D MCQ Rearrangement Set 14 MCQ Morphology of flowering plants MCQ Structural Organization In Animals MCQ Alchohols MCQ Accounts Fundamental MCQ Alkyl and Aryl Halides MCQ Coding MCQ Time and Work MCQ Aldehydes and Ketones MCQ