A can do a job in 16 days, B can do same job in 12 days. With the help of C they did the job in 4 days. C alone can do the same job in how many days ?

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A can do a job in 16 days, B can do same job in 12 days. With the help of C they did the job in 4 days. C alone can do the same job in how many days ?

A. $9 \frac{3}{5} d a y s$

B. $8 \frac{3}{5} d a y s$

C. $5 \frac{1}{2} d a y s$

D. $4 \frac{1}{2} d a y s$

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In this question we having, A's work, B's work and A+B+C work. We need to calculate C's work.
We can do it by,
(A+B+C)'s work - (A's work + B's work).
Let's solve it now:
C's 1 day work =

\frac{1}{4} - (\frac{1}{16} + \frac{1}{12}) = (\frac{1}{4} - \frac{7}{48}) = \frac{5}{48}

So C can alone finish the job in 48/5 days,
Which is =

9 \frac{3}{5} d a y s

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Accepted Answer

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A can do a job in 16 days, B can do same job in 12 days. With the help of C they did the job in 4 days. C alone can do the same job in how many days ?

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