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A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to empty the tank completely will be

A. (2A√H₁)/(Cd × a√2g)

B. (2AH₁)/(Cd × a√2g)

C. (2AH₁3/2)/(Cd × a√2g)

D. (2AH₁²)/(Cd × a√2g)

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