An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank, and g = Acceleration due to gravity)
tanθ = a/g
tanθ = 2 a/g
tanθ = a/2g
tanθ = a2/2g
Correct Answer :
A. tanθ = a/g
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