The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person ?

A. 30

B. 25

C. 20

D. 15

Correct Answer :

A. 30

Let's take the present age of the elder person = x and the present age of the younger person = x 16 (x 6) = 3 (x-16-6) => x 6 = 3x 66 => 2x = 60 => x = 60/2 = 30