What will be output if you will compile and execute the following c code?
#include
int main(){
int i=320;
char *ptr=(char *)&i;
printf("%d",*ptr);
return 0;
}
int main(){
int i=320;
char *ptr=(char *)&i;
printf("%d",*ptr);
return 0;
}
1
64
320
Compiler Error
Correct Answer :
B. 64
As we know size of int data type is two byte while char pointer can pointer one byte at time.
Memory representation of int i=320
So char pointer ptr is pointing to only first byte as shown above figure.
*ptr i.e. content of first byte is 01000000 and its decimal value is 64.
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