Their algebraic sum is zero
Their lines of action are at equal distances
The algebraic sum of their moments about any point in their plane is zero
The algebraic sum of their moments about any point is equal to the moment of their resultant force about the same point.
IP = IG + Ah2
IP = IG - Ah2
IP = IG / Ah2
IP = Ah2 / IG
Output to the input
Work done by the machine to the work done on the machine
Mechanical advantage to the velocity ratio
All of the above
Limiting friction
Sliding friction
Rolling friction
Kinematic friction
Balance each other
Produce a couple and an unbalanced force
Are equivalent
Cannot balance each other
The tangent of the angle of friction is equal to coefficient of friction
The angle of repose is equal to angle of friction
The tangent of the angle of repose is equal to coefficient of friction
The sine of the angle of repose is equal to coefficient to friction
Coplanar concurrent forces
Coplanar non-concurrent forces
Like parallel forces
Unlike parallel forces
Potential energy
Kinetic energy
Power
None of these
Equal to
Less than
Greater than
None of these
ω/r
ω.r
ω2/r
ω2.r
Less than
Greater than
Equal to
None of these
g/2
g/3
g/4
None of these
mr2/2
mr2/4
mr2/6
mr2/8
Three forces acting at a point will be in equilibrium
Three forces acting at a point can be represented by a triangle, each side being proportional to force
If three forces acting upon a particle are represented in magnitude and direction by the sides of a triangle, taken in order, they will be in equilibrium
If three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two
15 N and 5 N
20 N and 5 N
15 N and 15 N
None of these
P × OA
P × OB
P × OC
P × AC
W sinθ
W cosθ
W secθ
W cosecθ
kg-m²
m²/kg.
kg/m²
kg/m
Force
Speed
Velocity
Acceleration
2mr2/3
2mr2/5
7mr2/3
7mr2/5
The two bodies will momentarily come to rest after collision
The two bodies tend to compress and deform at the surface of contact
The two bodies begin to regain their original shape
All of the above
n
n²
2n
2n - 1
Perfect
Imperfect
Deficient
None of these
0.1 joule/s
1 joule/s
10 joules/s
100 joules/s
Rolling friction
Dynamic friction
Limiting friction
Static friction
5
10
20
40
Inelastic bodies
Elastic bodies
Neither elastic nor inelastic bodies
None of these
Three forces acting at a point will be in equilibrium
Three forces acting at a point can be represented by a triangle, each side being proportional to force
If three forces acting upon a particle are represented in magnitude and direction by the sides of a triangle, taken in order, they will be in equilibrium
If three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two
Reducing the problem of kinetics to equivalent statics problem
Determining stresses in the truss
Stability of floating bodies
Designing safe structures
a2/8
a3/12
a4/12
a4/16